Optimal. Leaf size=198 \[ \frac{16 b^2 (a+b x)^{3/2} (-3 a B e+2 A b e+b B d)}{315 e (d+e x)^{3/2} (b d-a e)^4}+\frac{8 b (a+b x)^{3/2} (-3 a B e+2 A b e+b B d)}{105 e (d+e x)^{5/2} (b d-a e)^3}+\frac{2 (a+b x)^{3/2} (-3 a B e+2 A b e+b B d)}{21 e (d+e x)^{7/2} (b d-a e)^2}-\frac{2 (a+b x)^{3/2} (B d-A e)}{9 e (d+e x)^{9/2} (b d-a e)} \]
[Out]
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Rubi [A] time = 0.351453, antiderivative size = 198, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125 \[ \frac{16 b^2 (a+b x)^{3/2} (-3 a B e+2 A b e+b B d)}{315 e (d+e x)^{3/2} (b d-a e)^4}+\frac{8 b (a+b x)^{3/2} (-3 a B e+2 A b e+b B d)}{105 e (d+e x)^{5/2} (b d-a e)^3}+\frac{2 (a+b x)^{3/2} (-3 a B e+2 A b e+b B d)}{21 e (d+e x)^{7/2} (b d-a e)^2}-\frac{2 (a+b x)^{3/2} (B d-A e)}{9 e (d+e x)^{9/2} (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[(Sqrt[a + b*x]*(A + B*x))/(d + e*x)^(11/2),x]
[Out]
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Rubi in Sympy [A] time = 34.6386, size = 185, normalized size = 0.93 \[ - \frac{32 b^{2} \left (a + b x\right )^{\frac{3}{2}} \left (- A b e + \frac{B \left (3 a e - b d\right )}{2}\right )}{315 e \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{4}} - \frac{8 b \left (a + b x\right )^{\frac{3}{2}} \left (2 A b e - 3 B a e + B b d\right )}{105 e \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )^{3}} - \frac{4 \left (a + b x\right )^{\frac{3}{2}} \left (- A b e + \frac{B \left (3 a e - b d\right )}{2}\right )}{21 e \left (d + e x\right )^{\frac{7}{2}} \left (a e - b d\right )^{2}} - \frac{2 \left (a + b x\right )^{\frac{3}{2}} \left (A e - B d\right )}{9 e \left (d + e x\right )^{\frac{9}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b*x+a)**(1/2)/(e*x+d)**(11/2),x)
[Out]
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Mathematica [A] time = 0.449448, size = 177, normalized size = 0.89 \[ \frac{2 \sqrt{a+b x} \left (\frac{8 b^3 (d+e x)^4 (-3 a B e+2 A b e+b B d)}{(b d-a e)^4}+\frac{4 b^2 (d+e x)^3 (-3 a B e+2 A b e+b B d)}{(b d-a e)^3}+\frac{3 b (d+e x)^2 (-3 a B e+2 A b e+b B d)}{(b d-a e)^2}-\frac{5 (d+e x) (9 a B e+A b e-10 b B d)}{a e-b d}+35 (B d-A e)\right )}{315 e^2 (d+e x)^{9/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(Sqrt[a + b*x]*(A + B*x))/(d + e*x)^(11/2),x]
[Out]
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Maple [A] time = 0.014, size = 322, normalized size = 1.6 \[ -{\frac{-32\,A{b}^{3}{e}^{3}{x}^{3}+48\,Ba{b}^{2}{e}^{3}{x}^{3}-16\,B{b}^{3}d{e}^{2}{x}^{3}+48\,Aa{b}^{2}{e}^{3}{x}^{2}-144\,A{b}^{3}d{e}^{2}{x}^{2}-72\,B{a}^{2}b{e}^{3}{x}^{2}+240\,Ba{b}^{2}d{e}^{2}{x}^{2}-72\,B{b}^{3}{d}^{2}e{x}^{2}-60\,A{a}^{2}b{e}^{3}x+216\,Aa{b}^{2}d{e}^{2}x-252\,A{b}^{3}{d}^{2}ex+90\,B{a}^{3}{e}^{3}x-354\,B{a}^{2}bd{e}^{2}x+486\,Ba{b}^{2}{d}^{2}ex-126\,B{b}^{3}{d}^{3}x+70\,A{a}^{3}{e}^{3}-270\,A{a}^{2}bd{e}^{2}+378\,Aa{b}^{2}{d}^{2}e-210\,A{b}^{3}{d}^{3}+20\,B{a}^{3}d{e}^{2}-72\,B{a}^{2}b{d}^{2}e+84\,Ba{b}^{2}{d}^{3}}{315\,{e}^{4}{a}^{4}-1260\,b{e}^{3}d{a}^{3}+1890\,{b}^{2}{e}^{2}{d}^{2}{a}^{2}-1260\,a{b}^{3}{d}^{3}e+315\,{b}^{4}{d}^{4}} \left ( bx+a \right ) ^{{\frac{3}{2}}} \left ( ex+d \right ) ^{-{\frac{9}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b*x+a)^(1/2)/(e*x+d)^(11/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*sqrt(b*x + a)/(e*x + d)^(11/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 2.50234, size = 959, normalized size = 4.84 \[ -\frac{2 \,{\left (35 \, A a^{4} e^{3} - 8 \,{\left (B b^{4} d e^{2} -{\left (3 \, B a b^{3} - 2 \, A b^{4}\right )} e^{3}\right )} x^{4} + 21 \,{\left (2 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} d^{3} - 9 \,{\left (4 \, B a^{3} b - 21 \, A a^{2} b^{2}\right )} d^{2} e + 5 \,{\left (2 \, B a^{4} - 27 \, A a^{3} b\right )} d e^{2} - 4 \,{\left (9 \, B b^{4} d^{2} e - 2 \,{\left (14 \, B a b^{3} - 9 \, A b^{4}\right )} d e^{2} +{\left (3 \, B a^{2} b^{2} - 2 \, A a b^{3}\right )} e^{3}\right )} x^{3} - 3 \,{\left (21 \, B b^{4} d^{3} - 3 \,{\left (23 \, B a b^{3} - 14 \, A b^{4}\right )} d^{2} e +{\left (19 \, B a^{2} b^{2} - 12 \, A a b^{3}\right )} d e^{2} -{\left (3 \, B a^{3} b - 2 \, A a^{2} b^{2}\right )} e^{3}\right )} x^{2} -{\left (21 \,{\left (B a b^{3} + 5 \, A b^{4}\right )} d^{3} - 9 \,{\left (23 \, B a^{2} b^{2} + 7 \, A a b^{3}\right )} d^{2} e +{\left (167 \, B a^{3} b + 27 \, A a^{2} b^{2}\right )} d e^{2} - 5 \,{\left (9 \, B a^{4} + A a^{3} b\right )} e^{3}\right )} x\right )} \sqrt{b x + a} \sqrt{e x + d}}{315 \,{\left (b^{4} d^{9} - 4 \, a b^{3} d^{8} e + 6 \, a^{2} b^{2} d^{7} e^{2} - 4 \, a^{3} b d^{6} e^{3} + a^{4} d^{5} e^{4} +{\left (b^{4} d^{4} e^{5} - 4 \, a b^{3} d^{3} e^{6} + 6 \, a^{2} b^{2} d^{2} e^{7} - 4 \, a^{3} b d e^{8} + a^{4} e^{9}\right )} x^{5} + 5 \,{\left (b^{4} d^{5} e^{4} - 4 \, a b^{3} d^{4} e^{5} + 6 \, a^{2} b^{2} d^{3} e^{6} - 4 \, a^{3} b d^{2} e^{7} + a^{4} d e^{8}\right )} x^{4} + 10 \,{\left (b^{4} d^{6} e^{3} - 4 \, a b^{3} d^{5} e^{4} + 6 \, a^{2} b^{2} d^{4} e^{5} - 4 \, a^{3} b d^{3} e^{6} + a^{4} d^{2} e^{7}\right )} x^{3} + 10 \,{\left (b^{4} d^{7} e^{2} - 4 \, a b^{3} d^{6} e^{3} + 6 \, a^{2} b^{2} d^{5} e^{4} - 4 \, a^{3} b d^{4} e^{5} + a^{4} d^{3} e^{6}\right )} x^{2} + 5 \,{\left (b^{4} d^{8} e - 4 \, a b^{3} d^{7} e^{2} + 6 \, a^{2} b^{2} d^{6} e^{3} - 4 \, a^{3} b d^{5} e^{4} + a^{4} d^{4} e^{5}\right )} x\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*sqrt(b*x + a)/(e*x + d)^(11/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b*x+a)**(1/2)/(e*x+d)**(11/2),x)
[Out]
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GIAC/XCAS [A] time = 0.331064, size = 857, normalized size = 4.33 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*sqrt(b*x + a)/(e*x + d)^(11/2),x, algorithm="giac")
[Out]